在网上是找到了解密的方法,得一个文件挨一个文件地打开,复制,粘贴,解密,再复制,再粘贴,再保存......

如果一个ASP程序有几百个文件???

解决办法来了..

decode.asp

<% @Language="javascript" %>
<%

/*
*--------------- decode.asp -----------------
* 功能:遍历某个目录下的所有文件,对加密过的.asp文件
*      进行解密,并写入源文件中.
* 实例:单个文件解密
* Response.Write(DncodeFile(Server.MapPath("conn.asp")));
* 实例:目录下所有文件解密.
* DncodeFolderFiles(Server.MapPath("xml"))
* author:wanghr100(灰豆宝宝.net)
* update:2004-5-17 11:31
*--------------- decode.asp -----------------
*/

function DncodeFile(sFilePath)
{
/*
*--------------- DncodeFile(sFilePath) -----------------
* DncodeFile(sFilePath)
* 功能:打开文件sFilePath,Encode解密,重写该文件.
* 参数:sFilePath,字符串,文件的路径.
* 返回:sFilePath,文件的路径.
* 实例:Response.Write(DncodeFile(Server.MapPath("conn.asp")));
* author:wanghr100(灰豆宝宝.net)
* update:2004-5-17 0:58
*--------------- DncodeFile(sFilePath) -----------------
*/
    var ForReading = 1, ForWriting =2, ForAppending =8;
    var fso = Server.CreateObject("Scripting.FileSystemObject");
    var f = fso.OpenTextFile(sFilePath,ForReading,true);
    sFileText = f.ReadAll();
    f.Close();
    sDncodeText = strdec(sFileText)
    var f = fso.OpenTextFile(sFilePath,ForWriting,true);
    f.Write(sDncodeText);
    f.Close();
    //return sDncodeText;
    return sFilePath;
}

function GetFilesPath(sFolderPath)
{
/*
*--------------- GetFilesPath(sFolderPath) -----------------
* GetFilesPath(sFolderPath)
* 功能:遍历sFolderPath目录下的所有文件.返回数组.存储文件路径.
* 参数:sFolderPath,字符串,目录绝对路径.
* 实例:Response.Write(GetFilesPath(Server.MapPath("xml")))
* update:2004-5-12 8:33
* author:wanghr100(灰豆宝宝.net)
*--------------- GetFilesPath(sFolderPath) -----------------
*/
    var sFilePath = new Array();
    var fso = Server.CreateObject("Scripting.FileSystemObject");
    var oFolder = fso.GetFolder(sFolderPath);
    var oSubFolders = oFolder.SubFolders;
    var oFiles = oFolder.Files;
    icount = oFiles.Count;

    var enmFiles = new Enumerator(oFiles);
    for(;!enmFiles.atEnd();enmFiles.moveNext())
    {
        sFilePath[sFilePath.length] = enmFiles.item().Path
    }

    var enmFolders = new Enumerator(oSubFolders);
    for(;!enmFolders.atEnd();enmFolders.moveNext())